An easier to understand password cracking system for
Spiritual Warfare. Made by George Schott (soxandfur@aol.com)
If you would like the program that does this work for
you, instead of trying to crypt on your own, you are
encouraged to email me.
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More on password cracking - George Schott
It took me a minute to figure out MJHayes's system, and
I consider myself skilled, so let me try to explain this
a bit simpler. Here is an example password :
g98Mdfhj67twK1.B
tTNzVogC00RRIDDh
The first 8 characters (g through j in the password)
represent your name. This guy's name is Adam. The first
letter in his name is A, which on the chart below is 10.
So you take 10 and add 32 to get 42 which is a g, which
is the first character in the password. If your number is
over 55 you subtract 64. I will demonstrate in the next character.
The next character of his name is a d, which is a 39. For
the second character you add 34, giving you a total of 73.
Subtract 64 since it's over 55, and it will give you 9, which
is a 9. 9 is the second character in the password. Do this
for the third and fourth characters of the name (add 36 and 38
this time). For characters 5-8, since there is no letters, you
add -1 to the values you add on to (40, 42, 44, 46), that
also have a MOD of 64, which you dont use for those characters,
in that instance.
'0'= 0, '1'= 1, '2'= 2, '3'= 3, '4'= 4, '5'= 5, '6'= 6, '7'= 7,
'8'= 8, '9'= 9, 'A'= 10, 'B'= 11, 'C'= 12, 'D'= 13, 'E'= 14, 'F'= 15
'G'= 16, 'H'= 17, 'I'= 18, 'J'= 19, 'K'= 20, 'L'= 21, 'M'= 22, 'N'= 23
'O'= 24, 'P'= 25, 'Q'= 26, 'R'= 27, 'S'= 28, 'T'= 29, 'U'= 30, 'V'= 31
'W'= 32, 'X'= 33, 'Y'= 34, 'Z'= 35, 'a'= 36, 'b'= 37, 'c'= 38, 'd'= 39
'e'= 40, 'f'= 41, 'g'= 42, 'h'= 43, 'i'= 44, 'j'= 45, 'k'= 46, 'l'= 47
'm'= 48, 'n'= 49, 'o'= 50, 'p'= 51, 'q'= 52, 'r'= 53, 's'= 54, 't'= 55
'u'= 56, 'v'= 57, 'w'= 58, 'x'= 59, 'y'= 60, 'z'= 61, '!'= 62, '.'= 63
The 9th character is your location :
'0'= Park '1'= Downtown '2'= Slums '4'= Airport
'6'= Prison '7'= Warehouse '8'= Hotels 'A'= Houses
'B'= Beach 'C'= Shipyard 'D'= Woods 'L'= Demon's Lair
'W'= Boss 1 'X'= Boss 2 'Y'= Boss 3 'Z'= Boss 4
'a'= Boss 5 'b'= Boss 6 'c'= Final Boss
This character has a 6 for the 9th character and is in the prison.
The next section uses binary.
The 10th character is a 7, which means that you have the belt, brestplate, and
boots.
the Sword of the Spirit = 0
the Helmet of Salvation = 0
the Shield of Faith = 0
the Boots of the Gospel = 1
the Breastplate of Righteousness = 1
the Belt of Truth = 1
000111 is binary for 7.
If you don't know how to convert binary to decimal go to :
http://www.odsa.com/tools/binary.shtm
The 11th character is a t, which means that
Num Vials is greater than 128 = 1
Num Vials is between 64 and 127 OR if Num Vials is greater than 192 = 1
Ticket = 0
Raft = 1
Jawbone = 1
Torch = 1
110111 = 55 = 't'.
This character, Adam, has 255 vials which means that the first two digits are both
true,
and both get 1, and he does not have the railroad ticket, but he does have the
raft, jawbone, and torch.
The 12th character is a w, which means that this character has 2 anointing oils
and 10 heart containers.
Have 1 or 2 Anoiting oils = 1
Have 2 Anointing oils = 1
Have between 8 and 12 heart containers = 1
Have between 4 and 7 heart containers OR 12 heart containers = 0
Have 3 or 6 or 7 or 10 or 11 heart containers = 1
Have 3 or 5 or 7 or 9 or 11 heart containers = 0
11010 = 58 = w.
The 13th character is a K, which means that Adam has 20 half-hearts in his health.
Since his heart containers is 10 and he has max health this is 20 and 20 = K.
The 14th character is a 1, which means that Adam has 1 key.
The 15th character is a ., which means that because he has 255 vials, if you write
that in binary it is 11111111. Ignore the first two digits giving you 111111.
111111 in decimal is 63, which is the character '.' (period).
The 16th character is a B, which means that you look at your Faith points (doves),
which is 75. The binary value for 75 is 1001011. Look at only the last six digits
which are 001011 which in decimal is 11. And 11 = B.
The 17th character through the 26th characters are for if items such as heart
containers have been picked up or not.
The 27th character is represented by your pomegrantes and pears.
Adam has 3 pomegrantes, represented in binary as 11.
Adam has 3 pears, represented in binary as 11.
Each number uses three binary bits (Because the most it can be is 100 which is 4.)
The first 3 numbers are pomegrantes and the last 3 are pears.
011011 is binary for 27, which is R.
The 28th character is the same way except for grapes and apples, which
Adam also has 3 of each. 011011 is 27 which is R.
The 29th character is represented by the number of faith points and bananas.
Remember from earlier the number of faith points was 75 which was 1001011.
We ignored the 10 from that number earlier, so we use it here as the first two
digits for binary. This character also has 2 bananas, which is represented as 010.
A binary number has 6 bits, and 10 and 010 make 5. So instead we stick a 0 in
front
(010 is the same as 10) to make it 010010 which is binary for 18 which is a I.
The 30th and 31st characters are checksums. You add up all of the first 29 values.
For this you add up g+9+8+M+d+f+h+j+6+7+t+w+K+1+.+B+t+T+N+z+V+o+g+C+0+0+R+R+I.
Then you take that total and divide by 64. If you're interested in adding this,
42+9+8+22+39+41+43+45+6+7+55+58+20+1+63+11+55+29+23+61+31+50+42+12+0+0+27+27+18.
That number is 845. 845 / 64 = 13 remainder 13.
The remainder, 13, is the 30th character, which is a D.
The quotient, also 13, is the 31st character, which is also a D.
There is one last character which has not been solved / publicized yet that is
probably
a checksum.
Let's try changing this character's name from Adam to Napstar.
The original password was :
g98Mdfhj67twK1.B
tTNzVogC00RRIDDh
'0'= 0, '1'= 1, '2'= 2, '3'= 3, '4'= 4, '5'= 5, '6'= 6, '7'= 7,
'8'= 8, '9'= 9, 'A'= 10, 'B'= 11, 'C'= 12, 'D'= 13, 'E'= 14, 'F'= 15
'G'= 16, 'H'= 17, 'I'= 18, 'J'= 19, 'K'= 20, 'L'= 21, 'M'= 22, 'N'= 23
'O'= 24, 'P'= 25, 'Q'= 26, 'R'= 27, 'S'= 28, 'T'= 29, 'U'= 30, 'V'= 31
'W'= 32, 'X'= 33, 'Y'= 34, 'Z'= 35, 'a'= 36, 'b'= 37, 'c'= 38, 'd'= 39
'e'= 40, 'f'= 41, 'g'= 42, 'h'= 43, 'i'= 44, 'j'= 45, 'k'= 46, 'l'= 47
'm'= 48, 'n'= 49, 'o'= 50, 'p'= 51, 'q'= 52, 'r'= 53, 's'= 54, 't'= 55
'u'= 56, 'v'= 57, 'w'= 58, 'x'= 59, 'y'= 60, 'z'= 61, '!'= 62, '.'= 63
The characters Napstar are 23 36 51 54 55 36 53 -1. If we add the proper values
(32 34 36 38 40 42 44 and 46) you get 55 70 87 92 95 78 97 45. Modifying any
numbers over 64 gives you 55 6 23 28 31 14 33 45, which spells t6NSVEXj
If you add up all those values (chars 1 - 29) you get 831 which when divided by 64
gives you 12 remainder 63, so character 29 is a '.' (period) and character 30 is
a C. The last character for some odd reason is an A. I know this from trial and
error.
The new password for the same stats as Adam, but the name Napstar is :
t6NSVEXj67twK1.B
tTNzVogC00RRI.CA
Now, let's take Napstar, and let him have the Sword. This was is the 10th
character. So now the binary value would be 100111, which is 39, the letter
d.
Now the password is
t6NSVEXj6dtwK1.B
tTNzVogC00RRI.CA
Now we have to change the check sums. From the old sum of 831, the new sum (Adding
the change from 7 to d is 32) is 863, which when divided by 64 gives you 13 with
a remainder of 31. 31 is a V and 13 is a D. The new password is
t6NSVEXj6dtwK1.B
tTNzVogC00RRIVDB
You may have noticed I changed the last character to a B. That's one character
different, but you NEED TO DO it for it to work. Again, trial and error. I'm
not sure what the last character is though. This code does work, by the way.
I think you *may* run into a problem though if you try to get the sword while
you already have one. I'm not sure. Maybe the boss will just be dead.
Using my program you get a nice password :
t6NSVEXjB..yOZ..
tTNzVogC00aaqKGx
I *believe* the last digit is x. I was trying them all and thought that it didn't
work, but then i was at like the very bottom and it finally worked, worked well
too =) This password gets you all the fruit, armor, items, vials, doves, keys.
Note : Max keys are 35. Entering more (I entered 99 for the pass above) gets you
35 regardless lol.
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Included is the ORIGINAL password cracking system.
If you can't understand mine, try his.
(Note : His is untouched, and he has given me permission
to post this document.)
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Spiritual Warfare
Password partially cracked by mjhayes@cs.buffalo.edu
February 12, 1998
While I give Wisdom Tree credit for writing Christian Nintendo games, the
games themselves leave much to be desired. This game is little more than a
Legend of Zelda ripoff, and it uses a password system instead of battery-backup
savedata.
1. The first eight characters are an encryted form of your name.
Value of character 1= (the first character of your name+ 32) MOD 64
Value of character 2= (the second character of your name+ 34) MOD 64
Value of character 3= (the third character of your name+ 36) MOD 64
Value of character 4= (the fourth character of your name+ 38) MOD 64
Value of character 5= (the fifth character of your name+ 40) MOD 64
Value of character 6= (the sixth character of your name+ 42) MOD 64
Value of character 7= (the seventh character of your name+ 44) MOD 64
Value of character 8= (the eigth character of your name+ 46) MOD 64
2. The ninth character represents your location. Enter the appropriate
character using the lookup table below.
'0'= Park '1'= Downtown '2'= Slums '4'= Airport
'6'= Prison '7'= Warehouse '8'= Hotels 'A'= Houses
'B'= Beach 'C'= Shipyard 'D'= Woods 'L'= Demon's Lair
'W'= Boss 1 'X'= Boss 2 'Y'= Boss 3 'Z'= Boss 4
'a'= Boss 5 'b'= Boss 6 'c'= Final Boss
The password is 32 characters long, and the character set contains 2^6 or
64 characters, which means that a character in your password can represent a
6-bit binary number. At the bottom of the file is the character set, which you
will use to lookup the value of each character. One other bit of trivia; if you
do not enter a value for a character, the interpreter reads it as a period by
default.
3. The value of the tenth character is a 6-bit binary value. Each bit
represents a piece of the Armor of God; whether you have it or not. A 1 bit
means that you have the piece of Armor, a 0 bit means that you do not. The six
bits represent, from MSB to LSB (Most Significant Bit to Least Significant
Bit), the Sword of the Spirit, the Helmet of Salvation, the Shield of Faith,
the Boots of the Gospel, the Breastplate of Righteousness, and the Belt of
Truth.
4. The two MSBs of the value of the eleventh character represent the 2 MSBs
of the number of Vials of the Wrath of God in your inventory. You can have up
to 255 vials, which can be represented by an 8-bit binary number. These are the
2 MSBs, and the 6 LSBs are represented in another character. The 4 LSBs of the
value of the eleventh character represent, from MSB to LSB, the Railroad
Ticket, the Raft, Samson's Jawbone, and the Torch.
5. The two MSBs of the value of the twelfth character represent a 2-bit
binary value. Each of the two bits represent one of the two slots reserved in
your inventory for Anointing Oil. The four LSBs represent the number of heart
containers you have, from a range of 3..12. I don't remember if entering a
value out-of-range results in an invalid password or not. I think it results in
background corruption.
6. The value of the thirteenth character represents your health, in
half-heart increments. Again, I don't exactly remember what happens if you
enter a value out-of-range, but I think it will result in background
corruption.
The value of the fourteenth character represents the number of keys you
have, the value of the fifteenth character represents the 6 LSBs of the number
of Vials of the Wrath of God in your inventory, and the value of the sixteenth
character represents the 6 LSBs of the number of Faith Points you have. The 2
MSBs appear elsewhere.
7. The value of characters 17..26 are all 6-bit binary values. Each of the
bits represent a boolean value for everything you have obtained. In other
words, when you collect a heart container, Fruit of the Spirit, a piece of the
Armor of God, an item, etc. then a bit becomes a 1 which tells the game that
you have received that item, so the room containing the item should be empty if
you visit that room again.
8. The 3 LSBs of the value of the twenty-seventh character represent the
number of pears (meekness) you have. The 3 MSBs represent the number of
pomegranates (love) you have. The normal range for Fruits of the Spirit is
0..4. You can enter a number above the range, but nothing happens past 4.
The 3 LSBs of the value of the twenth-eighth character represent the
number of apples (patience) you have. The MSBs represent the number of grapes
(joy) you have. The 3 LSBs of the value of the twenty-ninth character represent
the number of bananas (faith) you have. The 2 MSBs represent the 2 MSBs of the
number of Faith Points you have. I don't know what the fourth LSB is for; it
probably is nothing.
9. Characters 30 and 31 are checksums. Add the values of the first 29
characters, then divide by 64. Character 31 is the divisor, character 30 is the
carry.
10. The last character is another checksum of some sort. For every
password, it must be exactly one value, but I can't figure it out! I think it
has something to do with the player name and the checksum, but I will give
recognition to the person who figures it out.
Here is the character set:
'0'= 0, '1'= 1, '2'= 2, '3'= 3, '4'= 4, '5'= 5, '6'= 6, '7'= 7,
'8'= 8, '9'= 9, 'A'= 10, 'B'= 11, 'C'= 12, 'D'= 13, 'E'= 14, 'F'= 15
'G'= 16, 'H'= 17, 'I'= 18, 'J'= 19, 'K'= 20, 'L'= 21, 'M'= 22, 'N'= 23
'O'= 24, 'P'= 25, 'Q'= 26, 'R'= 27, 'S'= 28, 'T'= 29, 'U'= 30, 'V'= 31
'W'= 32, 'X'= 33, 'Y'= 34, 'Z'= 35, 'a'= 36, 'b'= 37, 'c'= 38, 'd'= 39
'e'= 40, 'f'= 41, 'g'= 42, 'h'= 43, 'i'= 44, 'j'= 45, 'k'= 46, 'l'= 47
'm'= 48, 'n'= 49, 'o'= 50, 'p'= 51, 'q'= 52, 'r'= 53, 's'= 54, 't'= 55
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If anyone can figure out what the last character in the password stands for,
please email mjhayes@cs.buffalo.edu
